Correct Answer: Option B

Explanation

capacitors 5microfarad and 7microfarad are parallel to each other, hence effective capacitance = 5 + 7 = 12microfarad

12microfarad and 6 microfarad are in series then effective capacitance =

\(\frac{1}{6} + \frac{1}{12}\)

= \(\frac{3}{12}\)

then effective capacitance = \(\frac{12}{3}\) = 4microfarad

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