Correct Answer: Option A

Explanation

In general, the energy released during nuclear fission is given by Einstein's mass-energy equation, given by
\( E = \Delta MC^2 \)
Where \( \Delta m\) is the mass defect, and C is the speed of light.
Therefore
\( \Delta m = 0.01% \text{of} 1.0g = \frac{0.01}{100}\times 1.0g \)
= 1.0 \(\times 10^{-4} \)
= 1.0 \(\times 10^{-7}kg\)
\(\text{Energy Released } = \Delta MC^2 \)
= 1.0 \(\times 10^{-7} \times (3.0 \times 10^8)^2\)
= 1.0 \(\times 10^{-7} \times 9.0 \times 10^{16} \)
= 9.0 \(\times 10^9 J \)

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