A bead traveling on a straight wire is brought to rest at 0.2m by friction....

JAMB 2003

A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1 determine the work done by the friction

A. \( 2 \times 10^{-4}J \)
B. \( 2 \times 10^{-3}J \)
C. \( 2 \times 10^{1}J \)
D. \( 2 \times 10^{2}J \)

WAEC and NECO CBT App for Mobile Devices - Candidates, Schools, Centres, Resellers - 100% Offline -Download Now

Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts

Correct Answer: Option B

Explanation

Work done by friction = Friction force x Displacement from the relation, f = uR

where u = coefficient of friction; R= Normal reaction

F = u mg (R =mg)
= 0.1 x 0.01 x 10
work done = F x Displacement
= 0.1 x 0.01 x 10 x 0.2
= 0.002 or \( 2 \times 10^{-3}J \)

Previous Next

Go back to Phy classroom

Report an Error Ask A Question Download App