A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1 determine the work done by the friction

a

\( 2 \times 10^{-4}J \)

b

\( 2 \times 10^{-3}J \)

c

\( 2 \times 10^{1}J \)

d

\( 2 \times 10^{2}J \)

Download Offline App Ask a Question

Explanation

Correct Option
b

Video Explanation

No video available

Post your Contribution

Share:

Discussions (3)

Velapearl
2 months ago

coefficient of friction=friction/normal reaction (which is mass × gravity)

J

Quick Questions

Ask a Question

abdullahibabajide63

22nd June, 2026


1 comments
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments