An elastic material has a length of 36cm when a load of 40N is hung on it and a length of 45cm when a load of 60N is hung on it. The original length of the string is

De sage

1 year ago

guys I understood.
F1/L1-lo=F2/L2-lo
F1=40N
L1=36cm
lo=?
F2=60N
L2=45cm

using the formula substitute
40/36-lo=60/45-lo
cross multiply
40(45-lo)=60(36-lo)
open bracket
1800-40Lo=2160-60Lo
CLT
1800-2160=-60Lo+40Lo
-360=-20Lo
divide both sides by -20
Lo= -360/-20
lo=18cm

Moses1951

1 year ago

I did not even understand it

chinelotamjoy

10 months ago

where is not solution my school

Testimony031

1 year ago

Temporary Crnode encountered

Eduphy

10 years ago

(45-to)cm

chinelotamjoy

1 year ago

the solution of the answer is not there.