A force of 200N acts between two objects at a certain distance apart. The value of the force when the distance is halved is

agadido

3 years ago

Coming to think of it, why did i use moment of forces instead of Gravitational forces, so by the way lion has a point

Obashe

1 year ago

force is inversely proportional to the squared of the distance apart..
thus using
F1×r1² =F2 ×r2² you'll get N800

SteezyGirl25

11 months ago

The solution is incomplete

IbrahimYousup

5 years ago

The correct answer is C

isere_sieg

7 years ago

I disagree because the question didn't involve anything with gravity or mass.
recall that force is inversely proportion to length
I.e F1L1=F2L2
assuming the distance in question is 4m then we have
200*4=F2*2
F2=800/2
F2=400N

metroblack

1 year ago

incomplete explanation

FAITHACADEMY1

2 months ago

`DRYYY

Purple_phys

1 year ago

Unsanitized build exception detected: Unsupported operation: Temporary node CrNode encountered

Shukurat77

10 months ago

temporary node CrNode encountered

metroblack

1 year ago

wrong answer

GaloNazie

2 years ago

see,this thing is no supposed to bring any fight,i really think he is just playing,i often use words like that on my friend

wentir

2 months ago

If the distance is 4m then we have
F1xL1^2=F2xL2^2
200*16=F2*4
3200=4F2
F2=3200/4
F2=800N

THEY ARE CORRECT

wentir

2 months ago

L2^2/2

Abdulesun

4 years ago

Even from the question, we should be able to deduce that when two objects are at certain distance and were acted upon by a force of 200N, if the distance is now halved, what do you think the force will be? Definitely, half.
Therefore, the answer is 100N.....>>(C).