Two resistors 5Ω and 10Ω are arranged first in series and later in parallel to a 24V source, the ratio of total power dissipated in the series and parallel arrangements respectively is

Ozny

4 years ago

My school when did jamb options end with letter E

Vio1

2 years ago

It would have been better if this is solved and the correct answer is known.

Bunji

5 years ago

e

bbc5

2 months ago

yes not correct

Gddhhcv

2 years ago

I'm confused 😕 My school please we need a better explanation and answer for the question 🙏
Because according to my past question and answer there wrote 50:1 as the answer C 😔😔

ChikezieObinna

1 year ago

The answer is option C if you do the math. Please stop making these mistakes that can change the mindset of students in Nigeria because there are other CBT learning platforms that they would not be scared to try if these mistakes continue. I suggest all questions should be reviewed
and resolved to get the right answers.
Thank you for listening to my complaint.

NwonyePius

4 years ago

Option B is correct @myschool. please review this.
Solution
R in series = 5+10 = 15
R in parallel = (5*10)/(5+10)=10/3
P in series = (v*v)/I = (24*24)/15=38.4W
P in parallel = (v*v)/I=(24*24)/(10/3)=(576/3.333)=172.8W
P in series/ P in parallel=38.4/172.8= 0.222W
Now this is approximately 0.2W which is option B.