Physics
JAMB 2011
In an A.C circuit, the ratio of r.m.s value to peak value of current is
-
A.
2
-
B.
\( \frac{1}{2} \)
-
C.
\( \frac{1}{\sqrt{2}} \)
-
D.
\( \sqrt{2} \)
Correct Answer: Option C
Explanation
Irms = \( \frac{I_0}{\sqrt{2}} \)
\( \text{Therefore } \sqrt{2Irms} = I_0 \\
\frac{Irms}{I_0} = \frac{1}{\sqrt{2}} \)
There is an explanation video available below.
Report an Error
Ask A Question
Download App
Explanation Video
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}