The radioisotope \( ^{235}_{92}U \) decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?

Olayemiaccurate

7 years ago

1. Since, alpha particles have properties similar to the nuclear of helium ion [whic has atomic mass of 4 and atomic number of 2].
Therefore, any atom which exhibit alpha particles will have it atomic mass decrease by 4 and the atomic number decrease by 2 and so the questions says the atom exhibit two alpha particles
so, this is to say the atom will have it's atomic mass decrease by 8 and atomic number decrease by 4
2. The question also says the atom also exhibit 3beta particles and since beta particle have properties similar to electrode [which has the atomic mass of 0 and atomic number of -1
therefore any atom which exhibit beta particles has it's atomic number increase by one and the atomic mass does not change
so after we are through with alpha particle them we are going to make the atom to exhibit beta particle so.
I.235-8=227
92-4=88
II.227-0-0-0=227
88+1+1+1=91. Final answer