A 120V, 60W lamp is to be operated on 220V ac supply mains. calculate the value of non inductive resistance that would be required to ensure that the lamp is run on correct value

teebreezy101

7 years ago

p=IV
I= 60/120=0.5
R=V/I=120/0.5=240ohms
Resistance of 220v=220/0.5=440ohms
Effective resistance= 440-240= 200 ohms.... This is how it is solved take correction myschool

12funmilola13

1 year ago

## Calculating Resistance:
To operate the 120V, 60W lamp on 220V AC supply:

## Given Values:
1. Lamp voltage (V₁) = 120V
2. Lamp power (P) = 60W
3. Supply voltage (V₂) = 220V

## Lamp Current:
I = P / V₁ = 60W / 120V = 0.5A

## Required Resistance:
To drop the excess voltage (220V - 120V = 100V) at 0.5A:

R = V / I = 100V / 0.5A = 200Ω

The correct answer is *B. 200Ω*.