A 40KW electric cable was used to transmit electricity through a resistor of resistance 2.00Ω at 800V. The power loss as internal energy is
4.0 x 102W
5.0 x 102W
4.0 x 103W
5.0 x 103W
Explanation
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P=IV
P= 40KW = 40000W
I=?
V=800
40000=800 I
DBS BY 800
I=40000/800
50
Recall;Power.Loss= I²R
P.Loss=50²×2
= 2500×2
=5000
= 5×10³
Myschool is correct. Though the solution in my question is not visible.... pls can it be resolved. This has occurred thrice this yr
You guys should try and explain this thing Abeg 🙏. Seems there is an error in the question or so
To find the power loss as internal energy, we can use the formula:
Power (P) = Voltage (V) x Current (I)
We are given:
Power (P) = 40 kW = 40,000 W
Voltage (V) = 800 V
Resistance (R) = 2.00 Ω
Current (I) = Voltage (V) / Resistance (R)
= 800 V / 2.00 Ω
= 400 A
Power loss = I^2 x R
= (400 A)^2 x 2.00 Ω
= 160,000 x 2.00
= 320,000 W
Power loss = V^2 / R
= (800 V)^2 / 2.00 Ω
= 640,000 / 2.00
= 320,000 W
320,000 W is approximately equal to 3.2 x 10^5 W, which is closest to:
C. 4.0 x 10^3 W is not correct, but the closest answer is not available, however 3.2 x 10^5 W is closer to:
C. 4.0 x 10^5 W
Note: It seems there is a mistake in the options, the correct calculation is 3.2 x 10^5 W which is closer to 4.0 x 10^5 W than the other options.
