Correct Answer: Option D

Explanation

\( R = \frac{\rho L}{A}\)  \(\implies \rho\) = \(\frac{R.A}{L}\) = \(\frac{0.1 \times 3.14}{2} \left ( \frac{10^{-3}}{2} \right)^2\)

\(\therefore\) \(\rho\) = \(\frac{0.1 \times 3.14 \times 10^{-6}}{2 \times 4}\)

= 0.3925 x 10\(^{-7}\) OR 3.930 x 10 \(^{-8}\)Ωm

There is an explanation video available below.

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