If two charged plates are maintained at a potential difference of 3 kv, the work done in taking a charge of 600µc across the field is

a

0.8j

b

1.8j

c

9.0j

d

18.0j

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Explanation

Correct Option
b

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Discussions (4)

Eduphy
10 years ago

More explanation is needed here.

banitoobi
7 years ago

Qv÷1000
600×3÷1000=1.8j

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