The dimension of universal gravitational constant is……….?

Physics

JAMB 2015

A. \( M^{–1}L^3 T^{–2} \)
B. ML³T²
C. ML³
D. MLT^-2

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Correct Answer: Option A

Explanation

f α (MM ÷g²)

F(GMM ÷ r²) [G – gravitational constant]

GMM = Fr²

G = F0² ÷ MM = m × aπr² ÷ MM (f = ma)

= (m × m5^-2 × r²) ÷ MM

= (Kg.m5² × m²) ÷ Kg.Kg

=1 ÷ kg.m³.5²

The dimension mathematically representation have a quantities of M, L AND T

M (Mass) = kg, L (Length) = M, T (Time) second

G = kg^-1 m².5²(Using dimension rule)

M^-1.L³.T^-2

∴ The universal gravitational constant (G) =\( M^{–1}L^3 T^{–2} \)

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