The dimension of universal gravitational constant is……….?

a

\( M­^{–1}L^3 T^{–2} \)

b

ML3T2

c

ML3

d

MLT-2

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a

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Reedah6
2 years ago

f=Gm1m2/r^2
fr^2=Gm1m2
G=fr^2/m1m2
G=kgms^-2 x m^2/kg^2
G=m/s^2 x m^2 x 1/kg
G=kg^-1m^3s^-2
dimensional analysis:M^-1L^3T^-2

TakonMichelle
2 months ago

hi

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