Correct Answer: Option A

Explanation

F = \(\frac{Gm_1 m_2}{r^2}\)

\(M_1 = 10^{24}\)Kg, \(M_2 = 10^{27}\)Kg , r = \(10^{20}\)meters

(Note: the gravitational constant of G = \(6.67408×10^{-11}Nm^2/kg^2\))

F = \(\frac{(6.67 \times 10^{– 11 + 24 + 27})}{ 10^{40}} = 6.67 \times \frac{10^{40}}{10^{40}}\)

= 6.67N

f = 6.67N

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