The period of a simple pendulum X is 5s. What is the period of a simple pendulum Y which makes 50 vibrations in the same time it takes X to make 20 vibrations?

a

12.5s

b

2.5s

c

2.0s

d

1.2s

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Correct Option
c

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Discussions (5)

Award0001
2 years ago

Use this formula i came up with
TxVx = TyVy
5×20 = Ty × 50
100 = 50Ty
Ty = 100/50 = 2secs🌟🤝

victorirowa1
10 years ago

the answer is 2...frequency is number of ossilation per time i.e F=n/t while period is the reciprocal @ T=t/n i.e ....therefore 5=t/20=20*5=100 therefore T=100/50=2

victorirowa1
10 years ago

the answer is 2...frequency is number of ossilation per time i.e F=n/t while period is the reciprocal @ T=t/n i.e ....therefore 5=t/20=20*5=100 therefore T=100/50=2...,..WHERE T=PERIOD WHILE t=time

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