A body is projected vertically upwards with a speed of 10 ms-1 from a point 2m above the ground. Calculate the total time taken for the body to reach the ground. [g = 10ms-2]

a

1.00s

b

2.00s

c

2.18s

d

3.00s

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b

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Discussions (14)

chinexx
9 years ago

It is 2.18

MsJhannie
10 years ago

formulae is generated as below↓



V= U±gt

when the body is projected, V=0

therefore, U=gt .

t=u/g.

where, t= time taken to reach the maximum height.



Time taken to reach the ground= 2×time for max height.

T= 2u/g

Betterbyfar
1 year ago

u can follow this to arrive at the correct answer 2.18s
Firstly, the final velocity when the object reaches the ground, V = √(u²+2gh) gotten from V²= U²+2as.
where h, is the height above the ground, 2m, u is initial velocity 10m/s....
Secondly, the total time taken for the object projected from 2m above the ground to reach the ground again, t = (u+v)/g... gotten from v= u+at

inputting all the parameters, t is gotten as 2.18seconds.

elviso
10 years ago

this is very wrong please. do the calculation well and u'll get 2.18s

MAYC33
2 years ago

Answer is 2.18

Brodan1
2 years ago

What happened to the 2m above the ground?
Please explain

Angelaprecious
6 years ago

Pls what's the formula for max height and range with out using angle.
The 2m above the ground in the question not going to be used in calculating the total time taken.

Brodan1
2 years ago

The answer is totally wrong.
Urgent correction is needed to avoid confusing the students.
The total distance is maximum height+2m

donpre
1 year ago

It's a classic physics problem! Let's break it down step by step:

1. Initial velocity (u) = 10 m/s (upwards)
2. Initial height (h) = 2 m (above the ground)
3. Acceleration due to gravity (g) = 10 m/s² (downwards)
4. Final velocity (v) = 0 m/s (when the body reaches the ground)

Using the equation: v² = u² + 2gh

0² = 10² + 2(-10)(h + 2)

0 = 100 - 20h - 40

20h = 60

h = 3 m (total height from the ground to the maximum point)

Now, let's find the time taken to reach the maximum point:

v = u + gt

0 = 10 + (-10)t

t = 1 s (time taken to reach the maximum point)

Now, let's find the time taken to fall from the maximum point to the ground:

h = ut + (1/2)gt²

3 = 0 + (1/2)(-10)t²

t² = 0.6

t ≈ 0.77 s (time taken to fall from the maximum point to the ground)

Total time taken for the body to reach the ground:

t_total = t_up + t_down ≈ 1 s + 0.77 s ≈ 1.77 s

So, the total time taken for the body to reach the ground is approximately 1.77 seconds.

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