An object of mass m moves with a uniform speed v round a circular path of radius r. If its angular speed is \(\omega\), the magnitude of the centripetal force acting on it is
a
\(m \omega^2 r\)
b
\(\frac{mv^2}{r}\)
c
\(m \omega r\)
d
\(\frac{mv^2}{r^2}\)
Explanation
Correct Option
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Discussions (6)
prince hamsel
10 years ago
centripetal force is mv^2/r. and linear velocity in a circular path v=wr. insert the value of v=we into the other fomular it gives mw^2r
harrybryce
5 years ago
Pls my school kindly change the ans cus it is A
The Question is asking for centripetal force in respect to angular velocity so it should be A
