Ice of mass 10g at 5°C was completely converted to water at 0°C, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg\(^{-1}\)K\(^{-1}\), specific latent heat of fusion of ice = 336 Jg\(^{-1}\)]

bobby204

6 years ago

option C is meant to be 3465J and not 3265

kushylyon

9 years ago

i got 3465...but I was surprised to see 3265 in the option and not 3465. I still chosed it sha, since they are close

isimemen4279

4 years ago

the correct annser should be B . Taking into consideration that initial temp =5 and final temperature is =0
therefore change in temperature = final temperature- initial temperature thus =0-5=-5
thus
heat used = ml +mc x change in temperature
= (10x336) + ( 10x2.1x-5)
= 3360 +(-105)
= 3360 - 105
=3255 J

pls correct this error

Ayeenscal

4 years ago

At room temperature or standard conditions, the temperature of ice is not likely to be above 0°C. Hence the correct question should be 'ice of mass 10g at -5°C'.