A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms\(^{-2}\)]. Calculate the speed of projection
To find the speed of projection, we can use the formula for the time of flight of an object projected vertically upwards:
\(t = \frac{2u}{g}\)
where:
- \( t \) is the total time of flight (1.2 s),
- \( u \) is the initial speed of projection,
- \( g \) is the acceleration due to gravity (10 m/s²).
Rearranging the formula to solve for \( u \):
\(u = \frac{gt}{2}\)
Substituting the values:
\(u = \frac{10 \, \text{m/s}^2 \times 1.2 \, \text{s}}{2} = \frac{12}{2} = 6 \, \text{m/s}\)
Thus, the speed of projection is \( 6 \, \text{m/s} \).
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