An object is placed 10cm from a converging lens of foal length 15cm. Calculate the magnification of the image formed
3.0
1.5
0.6
0.3
Explanation
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U=10, using the mirror formula :1/V + 1/U=1/F you can find the value of V=30 then substitute to M=V/U to find magnification =30/10=3.0
The magnification of the image formed by a lens is given by the formula:
m = -di/do
where m is the magnification, di is the image distance, and do is the object distance.
For a converging lens, the focal length f is positive. The thin lens equation relates the focal length, object distance, and image distance as:
1/f = 1/do + 1/di
Substituting the given values, we get:
1/15 = 1/10 + 1/di
1/di = 1/15 - 1/10
1/di = (2/30) - (3/30)
1/di = -1/30
di = -30 cm
Note that the negative sign indicates that the image is formed on the opposite side of the lens from the object, which is consistent with the fact that the lens is converging.
Substituting the object and image distances into the magnification formula, we get:
m = -di/do = -(-30 cm)/10 cm = 3
Therefore, the magnification of the image formed is 3, and the correct answer is option A.
the selected answer is wrong the answer ought to A(3cm)
the explantion is also incorrect
using the mirror formula the image distance ought to be -30cm
substituting this into
m=v/u
m= -30/10
m= 3cm
Selected answer is wrong. Correct answer is 3.0. when an object is between the pole and optical centre of a converging lens. An enlarged, virtual image is formed .
The answer is actually 0.6 because a converging lens will produce a virtual image and the focal length is negative
