The focal length of the eye-piece of an astronomical telescope is f1, while the focal length of the object is f2. Fro normal adjustment, the angular magnification is given by
a
\(\frac{f_2}{f_1}\)
b
1 - \(\frac{f_2}{f_1}\)
c
\(\frac{f_2}{f_1}\) - 1
d
\(\frac{f_1}{f_2}\)
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tochukwuemmanuel
10 years ago
The answer is A the angular magnification for telescopes it's the ratio of the objective lense to that of the eye piece.
