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A coin is pushed from the edge of a laboratory bench with a horizontal velocity...

Physics
WAEC 2011

A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
  • A. 0.75m
  • B. 2.25m
  • C. 8.22m
  • D. 15.00m
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Correct Answer: Option C
Explanation
S = U\(\sqrt{\frac{2h}{g}}\)

= 15\(\sqrt{\frac{2 \times 1.5}{10}}\)

= 8.22m

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