A coin is pushed from the edge of a laboratory bench with a horizontal velocity of 15.0 ms-1. If the height of the bench from the floor is 1.5m, calculate the distance from the foot of the bench to the point of impact with the floor [g = 10ms-2]
a
0.75m
b
2.25m
c
8.22m
d
15.00m
Explanation
Correct Option
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Brightonexcellent
1 year ago
U = Horizontal velocity =15 m/s. (given)
T = Time taken to fall
R = U × T
Also, H = 1/2 g t (square)
1.5 = 1/2 (10×t square)
3 = 10 × t (square)
t = √(3/10) = √0.3
R = U × T
Range = 15 × √0.3
R = 8.215
R = 8.22m. (C is correct)

