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a body is projected horizonatlly from the top of a cliff 45m above the ground....

Physics
WAEC 2010

a body is projected horizonatlly from the top of a cliff 45m above the ground. if the body lands at a distance 30m from the foot of the cliff, calculate the speed of projection. [g = 10ms-2]

  • A. 10ms-1
  • B. 15ms-1
  • C. 20ms-1
  • D. 30ms-1
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Correct Answer: Option A
Explanation

from, H = \(\frac{1}{2}\)gt\(^2\)

45 =  \(\frac{1}{2}\) x 10 x t\(^2\)

45 = 0.5 x 10 t\(^2\)

45 = 5t\(^2\)

t\(^2\) = \(\frac{45}{5}\) = 9

t = \(\sqrt{9}\) = 3s

But distance = velocity x time

V = \(\frac{D}{t}\) = \(\frac{30}{3}\) = 10m/s


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