A cell of e.m.f. 1.5V is connected in series with a resistor of resistance 3.0\(\Omega\). A voltmeter connected across the cell registers 0.9V. Calculate the internal resistance of the cell
a
2.0\(\Omega\).
b
3.0\(\Omega\).
c
5.0\(\Omega\).
d
6.0\(\Omega\).
Explanation
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AmaraChris
1 year ago
V/R = e.m.f/R+r
0.9/3 = 1.5/3+r
0.9×3+r = 1.5×3
2.7+r = 4.5
r = 4.5-2.7
r = 1.8
approximately 2.0 ohms
