An isolated metal sphere of radius R, carrying an electric charge Q, is situated in the medium of relative permitivity, Er. A test charge is placed at a point p, distance r from the surface of the sphere. Let Eo represent the permitivity of free space. The magnitude of the electric field intensity at P is given by the expression
a
\(\frac{Q}{4 \pi E_o E_r r^2}\)
b
\(\frac{Q}{4 \pi E_o E_r(R + r)^2}\)
c
\(\frac{Q}{4 \pi E_o E_r(R - r)^2}\)
d
\(\frac{Q}{4 \pi E_o E_rR^2}\)
Explanation
Correct Option
dNo explanation available
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Discussions (4)
red_kwatwa
2 months ago
SORRY BUT OPTION B is correct
if the answer is D, then my school did not put their question clearly. It means they meant r=0
3BYKE
4 years ago
a is much more correct, cos the small letter r is the distance from the surface of the Sphere
