The period of a simple pendulum of length 80.0cm was found to have doubled when the length of the pendulum was increased by X. Calculate X.

Kerap23anxin

2 years ago

Well looking closely this is period of s simple pendulum bob.
The formular is; T1÷T2=squareroot of l1/swuareroot ofl2.
Moving further l1 is 80 , l2 is 80 +x, T1 is T , T2 is 2T.
Therefore; T1/T2=squareroot of l1/ squareroot of l2.
Inputing values we have
T/2T=squareroot of 80/squareroot of 80+x
Eliminate squareroot and square both T's at the opposite side.
Then u have T^2/ 2T^2 = 80/80+x
cross multiply and get ; 80×4T^2 = T^2 (80+x)
The T^2 cancels at both sides
320= 80+x
collect like terms; x= 320 - 80
x= 240m.

lilycoco

4 years ago

pls explain