A body of volume 0.046m3 is immersed in a liquid of density 980kgm-3 with \(\frac{3}{4}\)...

WAEC 2009

A body of volume 0.046m³ is immersed in a liquid of density 980kgm^-3 with \(\frac{3}{4}\) of its volume submerged. Calculate the upthrust on the body. [g = 10ms^-2]

A. 11.27N
B. 33.81N
C. 112.70N
D. 338.10N

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Correct Answer: Option D

Explanation

M = D x V

= 980 x 0.046 x \(\frac{3}{4}\) = 33.81kg

upthrust = mg = 33.81 x 10

= 338.1N

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Correct Answer: Option D

Explanation

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