Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[\(\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}\)]

Chidera2107

1 year ago

wait oo
this is not the question i saw when i was writing this
cor this exam is messing with my eyes

Tareoka

1 year ago

the answer is correct but the calculations they gave is wrong, its 1.44 × 10-⁷N

splenzye

2 years ago

force in an electric field= q1q2/4π£r²
and distance= r=5cm=0.05m
q1=q2=q =2*10e-10
1/4π£ = 9.00*10⁹
F = 9.00*10⁹ * (2*10–¹⁰)² / (0.05)²
F= 1.44*10-⁷N

Etugo

9 years ago

(9x4)/5 = 7.2........

The answer must start without 7.2 I.e B or C

Vivian125

2 years ago

the answer is D

Prince2006

3 years ago

The question answer and calculation are not correct

Etugo

9 years ago

Sorry

I meant the answer must start with 7.2