A block of mass 4.0kg causes a spiral spring to extend by 0.16m from its unstretched position. The block is removed and another body of mass 0.50kg is hung from the same spiral spring. If the spring is then stretched and released, what is the angular frequency of the subsequent motion? [g = 10 ms -2]
a
10\(\sqrt 5\) rads-1
b
5\(\sqrt 2\) rads-1
c
5 rads-1
d
\(\sqrt 5\) rads-1
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DAVIDEX112
1 year ago
in these question,
m=4kg,e=0.16m,g=10ms^-2.
you are asked to find the angular frequency W (which is in rads^-1)
and we know that W=2πF
NB: you aren't asked to find the angular period or normal angular velocity, you are asked to find angular frequency which is W=2πf.
so let's look for the period(T),so that we can substitute it into F=1/T to find our frequency
T=2π√m/√k
=2π√4/√0.16=2π√25=2π×5=10π
so our T is 10π so let's substitute our answer into F=1/T=1/10=0.1πHz
W=2πf=2×3.142×0.1×3.142=1.9744
