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A 500kV is applied across an X-ray tube. Calculate the maximum velocity of the electrons...

Physics
WAEC 2006

A 500kV is applied across an X-ray tube. Calculate the maximum velocity of the electrons produced [Me = 9.1 x 10\(^{-31}\)kg, e = 1.6 x 10\(^{-19}\)C]

  • A. 4.2 x 108ms-1
  • B. 1.9 x 108ms-1
  • C. 4.2 x 105ms-1
  • D. 1.8 x 105ms-1
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Correct Answer: Option A
Explanation

500Kv = 5 x 10\(^5\)V

E = Qv = \(\frac{1}{2}\)mv\(^2\)

E = 1.6 x 10\(^{-19}\) x 9.1 x 10\(^{-31}\) = 8 x 10\(^{-14}\)

8 x 10\(^{-14}\) =  \(\frac{1}{2}\)mv\(^2\)

8 x 10\(^{-14}\) = \(\frac{1}{2}\) x 9.1 x 10\(^{-31}\) x v\(^2\)

8 x 10\(^{-14}\) = 4.55 x 10\(^{-31}\) x v\(^2\)

v\(^2\) = \(\frac{8 \times 10^{-14}}{4.55 \times 10^{-31}}\) = 1.758 x 10\(^{17}\)

v = \(\sqrt{1.758 \times 10^{17}}\) = 4.2 x 10\(^8\)m/s


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