a cell of e.m.f. 1.5V and internal resistance 1.0\(\Omega\) is connected to two resistor of...

WAEC 2006

a cell of e.m.f. 1.5V and internal resistance 1.0\(\Omega\) is connected to two resistor of resistance 2.0\(\Omega\) and 3.0\(\Omega\) in series. Calculate the current through the resistors

A. 0.25A
B. 0.30A
C. 0.35A
D. 0.50A

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Correct Answer: Option A

Explanation

I = \(\frac{E}{R + r} = \frac{1.5}{5 + 1}\)

= \(\frac{1.5}{6} = 0.25A\)

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a cell of e.m.f. 1.5V and internal resistance 1.0\(\Omega\) is connected to two resistor of...

Correct Answer: Option A

Explanation

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