a cell of e.m.f. 1.5V and internal resistance 1.0\(\Omega\) is connected to two resistor of resistance 2.0\(\Omega\) and 3.0\(\Omega\) in series. Calculate the current through the resistors
a
0.25A
b
0.30A
c
0.35A
d
0.50A
Explanation
Correct Option
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auumar0@gmail.com
10 years ago
Here is an explanation:
From I=E/R+r
I=1.5/5+1 =1.5/6
I=0.25A.
REF: From Ohms law
