An electron of mass m and charge \(\Box\) enters a uniform electric field between two metal plates P and q separated by a distance d. P is maintained at a potential V while Q is earthed. Determine an expression for the magnitude of the acceleration of electron through the field
a
\(\frac{eV}{md}\)
b
\(\frac{d}{meV}\)
c
\(\frac{md}{eV}\)
d
\(\frac{e}{Vmd}\)
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Roman regin
10 years ago
Yeah! A is correct.
F=ma
F=Eq. I.e. electric field intensity multiply by charge which is also e.
Ma=Ee Note: V=Ed. Therefore E= V/d.
Ma=Ve/d.
a=/(Ve)/(dm).
