Physics
WAEC 2006
A quantity of steam at 100
oC condenses to water at the same temperature by releasing 6.9 x 10
4J of energy. Calculate the mass of the condensed steam. [specific latent heat of vaporization of eater = 2.3 x 10
6 J kg
-1]
-
A.
3.0 x 10-1 kg
-
B.
3.0 x 10-2 kg
-
C.
3.0 x 10-3 kg
-
D.
3.0 x 10-4 kg
Correct Answer: Option B
Explanation
M = \(\frac{Q}{T} = \frac{6.9 \times 10^{4}}{2.3 \times 10^6} = 3 \times 10^{-2} kg\)
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