How long will it take to heat 3kg of water from 28oC to 88oC in an electric kettle taking 6a from a 220V supply? [specific heat capacity of water = 4180 J kg-1K-1]
a
120s
b
570s
c
600s
d
836s
Explanation
Correct Option
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Newton2i
2 years ago
use the fomula
Energy = mcdelta theta
Energy = ivt
ivt = mcdelta theta
6 x 220 x t = 3 x 4180 x 88 -28
6 x 220 x t = 3 x 4180 x 60
t = 3 x 4180 x 60 / 6x 220 = 570sec
