Physics
WAEC 2005
a chemical cell of internal resistance 1\(\Omega\) supplies electric current to an external resistor of resistance 3\(\Omega\). Calculate the efficiency of the cell
-
A.
75%
-
B.
50%
-
C.
33%
-
D.
25%
Correct Answer: Option A
Explanation
R = \(r_1 + R = 1 + 3 = 4\Omega\)
\(\frac{3}{4} \times \frac{100}{1} = 75\)%
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}