A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor

Rx.Nino

2 years ago

The answer is supposed to be 0.12C and not any of the options privided.

WCE

4 months ago

charge=capacitance * voltage
= 600*10^-6*200
multiply carefully
=0.12Coulumbs

Mariogaji

1 year ago

oh mehn, i didn't see 0.12 so i assumed they didn't care about the 10^-6

Velapearl

2 months ago

it's 0.12 😪

Ablest

1 month ago

no correct option