Calculate the energy stored in a 20\(\mu F\) capacitor. If the p.d between the plates is 40V

a

3.2 x 10-2J

b

1.6 x 10-2J

c

8.0 x 10-4J

d

4.0 x 10-4J

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Correct Option
b

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Discussions (3)

firelion
5 years ago

W=Q/v
20×10 ^-6 /40=8.0×10 ^-4

PRadiant
2 years ago

Energy stored in a Capacitor = 1/2 CV^2

OR
E = 1/2 QV

While, Workdone = QV

firelion
5 years ago

W=Q/v
20×10 ^-6 /40=8.0×10 ^-6

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