A nuclide X is produced by bombarding a nitrogen(N) nucleus with an alpha(\alpha\) particle with the release of heavy hydrogen(D) nucleus as shown by the following nuclear equation, \(\alpha + ^{14}_{7}N \to ^p_qX + ^2_1D\). Determine the values of p and q in the equation

emmyakins

3 years ago

Alpha particle is an Helium nuclei (He) with a mass number of 4 and an atomic number of 2.

Mass number of nuclide X
4 + 14 = p + 2
18 = p + 2
p = 18 - 2 = 16

Atomic number of nuclide X
2 + 7 = q + 1
9 = q + 1
q = 9 - 1
q = 8

The correct answer is C.

CHUKWUKAMICHAEL

5 years ago

ANSWER IS A 12 AND 6
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