Physics
WAEC 2002
In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms
-2]
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A.
0.280kg
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B.
0.400kg
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C.
0.613kg
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D.
0.800kg
Correct Answer: Option D
Explanation
m = \(\frac{0.7 \times 40}{35} = 0.8kg\)
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