Physics
WAEC 2002
A spiral spring of natural length 30.0cm and force constant of 20Nm
-1 is compressed to 20.0cm. Calculate the energy stored in the spring
-
A.
0.1J
-
B.
1.0J
-
C.
10.0J
-
D.
100.0J
Correct Answer: Option A
Explanation
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)
= 0.1J
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