In the circuit diagram above. Calculate the energy stored in the inductor at resonance

a

0.100J

b

0.050J

c

0.010J

d

0.005J

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Explanation

Correct Option
b

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Discussions (4)

hooluumeedeeh
4 years ago

E=1/2Li^2

Where L=0.1
i=v/r
i=100/100
I=1
E=1/2Li^2
E=1/2×0.1×1×1
E=0.5


The reason we did not use impedance is because it is at resonance and at such Xl=Xc which we later equals 0

najeem kehinde
9 years ago

I seem the formula used was 1÷2pieFl or 1÷wl

Sterix10
9 years ago

Sumone pls explain

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