An electric bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally
a
296.7\(\Omega\)
b
400.0\(\Omega\)
c
512.2\(\Omega\)
d
806.7\(\Omega\)
Explanation
Correct Option
dVideo Explanation
No video available
Post your Contribution
Share:
Discussions (5)
Esixlove
8 years ago
the equation is P=v2/R; change of subject formula makes it R=v2/p, 220^2/60=806.666667.
please I'm typing with my phone.
