As the plates of a charged variable capacitor are moved closer together, the potential difference between them
As the plates of a charged variable capacitor are moved closer together, the potential difference between them decreases.
This is because the capacitance increases as the distance between the plates decreases. For a constant charge, the potential difference (V = \(\frac{\text{Q}}{\text{C}}\)) will decrease when capacitance (C) increases.
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