A wave has an amplitude equal to 4.0m, angular speed \(\frac{1}{3} \pi\) rads-1 and phase angle \(\frac{2}{3} \pi\) rad. The displacement y of the wave particle is given as
a
y = 4 sin \(\frac{\pi}{3}\)(t + 2)
b
y = 4 sin \(\frac{\pi}{3}\)(t + \(\frac{2}{\pi}\)
c
y = 4 sin \(\frac{\pi}{3} (2t + 1)\)
d
y = 4 sin \(\frac{\pi}{3}\) (t + 1)
Explanation
Correct Option
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CSN
5 years ago
y = A sin(wt + kx). the answer is obviously A na. why is myschool failing this kind of question?
