A piece of metal of mass 50g is cooled from 80oC to 20oC. Calculate the amount of heat lost. (specific heat capacity of the material of metal = 450Jkg-1K-1)
a
4.50 x 103J
b
2.25 x 103J
c
1.80 x 103J
d
1.35 x 103J
Explanation
Correct Option
dVideo Explanation
No video available
Post your Contribution
Share:
Discussions (2)
Evonb
6 years ago
Heat capacity=mc∆∅
Where; m=50g :.=0.05kg
C=450j/kgk; ∆∅=80-20
:.C=0.05×450×(80-20)
C=1350j or1.350×10^3j
