A machine of efficiency 80% is used to raise a body of mass 75kg through a vertical height of 3m in 30s. Calculate the power input. (g = 10ms-2)
Efficiency = \(\frac{ poweroutput}{powerinput}\)
but power output = \(\frac{ f \times s}{ t}\) = \(\frac{75 \times 10 \times 3}{ 30}\) = 75W
Efficiency = 80%, power output = 75w
then 0.8 = \(\frac{ 75}{powerinput}\)
power input = \(\frac{ 75}{0.8}\) = 93.75W.
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